Question

factorise x^2-3x-18 please help​

Answer 1

Answer:

${x}^{2} - 3x - 18$

${x}^{2} - 3x - 18 = 0$

${x}^{2} - 6x + 3x - 18 = 0$

$x(x - 6) + 3(x - 6) = 0$

$(x + 3)(x - 6) = 0$

$either \: (x + 3) = 0 \: or \: (x - 6) = 0$

$x = - 3 \: or \: 6$

Answer 2

Answer:

this method is the middle term splitting hope u like the answer