Question

factorise:(x^2-3x)^2-8(x^2-3x)-20​

Answer 1

Step-by-step explanation:

let (x²-3x) be a

so, new equations is a² - 8a - 20

a² -10a + 2a - 20

(a - 10)(a + 2)

Now Replacing a by x² - 3x

so,

(x² -3x-10)(x²-3x+2)

also, these equation have more roots

so, roots are

(x-5)(x+2)(x-1)(x-2)