Math, asked by subhram976, 7 months ago

factorise: (x^2-3x^2) -8(x^2-3x) -20​

Answers

Answered by preetimishra138162
1

Answer:5x^2-12x+10=0

Step-by-step explanation:(x^2-3x^2)-8(x^2-3x)-20

-2x^2-8x^2+24x-20

-10x^2+24x-20=0

-2(5x^2-12x+10)=0

5x^2-12x+10=0

hope it will help you

Answered by satyamjha786
0

Step-by-step explanation:

-2x^2-8x^2+24x-20=0

-10x^2+24x-20=0

5x^2+12x-10

D=144+200

D=344

x=(-12+-√D)/2

x=-6+-√86

either x=√86-6. or. x=-(√86+6)

the factors are

(x+√86-6)(x-6-√86)×-1

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