Question

Factorise x^2 - 3x^2 - 9x - 5

Answer 1

ɧɛƖƖơ ɱąɬɛ

I think the equation should be:

⇒ x³-3x²-9x-5

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Answer:

(x + 1), (x – 5) and (x + 1) are factors of the given polynomial.

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Step-by-step explanation:

GIVEN:

x³-3x²-9x-5________________(1)

TO FIND:

the factors of the given equation

SOLUTION:

equation (1)  can be simplified as,

⇒  $x^{3} +x^{2} -4x^{2} -4x-5x-5$

grouping together,

⇒   $x^{2} (x+1) -4x (x + 1) -5(x + 1)$

⇒  $(x + 1)(x^{2} -4x-5)$

⇒  $(x + 1)(x^{2} -5x + x-5)$  

⇒  $(x+1)(x(x-5)+1(x-5))$    

⇒  $(x+1)(x-5)(x+1)$

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∴the factors of the given equation are: (x+1),(x-5)and (x+1)

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ɧơ℘ɛ ıɬ ɧɛƖ℘ʂ ყơų  ☺

Answer 2

Answer:

Hey buddy !

Here is your answer :

x^2 - 3x^2 - 9x - 5 (given)

2x^2 - 9x - 5 = 0

2x^2 - ( 10-1)x - 5 = 0

2x^2 - 10x + x - 5 = 0

2x ( x-5 ) + 1 ( x-5) = 0

(2x +1) ( x-5) = 0

2x + 1 = 0. x - 5 = 0

2x = -1. x = 5

x = -1 / 2

Thank you..

Hope it will be helpful