Question

factorise:x^2+3x+2+ax+2a​

Answer 1

Question:-

• Factorise

• $\sf{\ x^{2}+3x+2+ax+2a=0}$

Concept Used :-

• First of all arrange them according to their variables

• Then we will factorise the equation

Explanation :-

$\implies\sf{\ x^{2}+3x+2+ax+2a=0}$

$\implies\sf{\ x^{2}+3x+ax+2+2a=0}$

$\implies\sf{\ x^{2}+(3+a)x+2(1+a)=0}$

• Divide (3+a) into two factors whose sum is (3+a) and product is 2(1+a)

$\implies\sf{\ x^{2}+(1+a)x+2x+2(1+a)=0}$

$\implies\sf{x(x+1+a)+2(x+1+a)=0}$

$\implies\sf{(x+1+a)(x+2)=0}$

• Now put these both with equal to zero for finding the value of x for this equation.

$\longrightarrow\bf{(x+1+a)=0}$

$\bf{\boxed{x=(-1-a)}}$

$\longrightarrow\bf{(x+2)=0}$

$\bf{\boxed{x= -2}}$

• So here After the factorization we get two value of x

Answer 2

Answer:

tanuj is correct for ur question,s answer