Question

Factorise-
(x^2-3x)(x^2-3x-1)-20
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Answer 1

ANSWER✔

$\sf\therefore (x^2-3x)(x^2-3x-1)-20$

$\sf\implies x^2 \times (x^2-3x-1) -3x \times (x^2-3x-1)-20$

$\sf\implies (x^4-3x^3-x^2)- (3x^3-9x^2-3x)-20$

$\sf\implies x^4-3x^3-x^2- 3x^3+9x^2+3x-20$

$\sf\implies x^4-3x^3-3x^3-x^2+9x^2+3x$

$\sf\implies x^4-6x^3-8x^2+3x-20$

$\large{\boxed{\bf{\implies x^4-6x^3-8x^2+3x-20}}}$

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Answer 2

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