Factorise (x^2- 3x) (x^2 -3x -1)- 20.
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1
answer will be this u have to let ex square minus three x
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here is your answer from your friend
(x^2-3x)(x^2-3x-1)-20
= x^4-3x^3-x^2-3x^3+9x^2+3x-20
= x^4-6x^3+8x^2+3x-20 Ans
(x^2-3x)(x^2-3x-1)-20
= x^4-3x^3-x^2-3x^3+9x^2+3x-20
= x^4-6x^3+8x^2+3x-20 Ans
AryaDhole:
The answer is 1/35(1+7a)(1+5a)
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