factorise [x-2/3y]³
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\textbf{Answer:}Answer:
(x-2/3y)³ - (x+2/3y)³
=[x³-(2/3y)³-3(x)(2/3y) (x-2/3y)
=[x³+2/3y)³+3(x)(2/3y) ( x+2/y)
=[x³-8/27y³-2x²y+4/3xy²)-[x³+8/27y³+2x²y+4/3xy²)
=-16/27y³-4x²y
\textbf{Hope it helps you!}Hope it helps you!
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