Question

factorise x^2÷4a^2-y^2÷9b^2​

Answer 1

Answer:

Step-by-step explanation :here

applied rule is a^2-b^2=(a+b)(a-b)

Answer 2

Answer:

( x/2a + y/ 3b ) ( x/2a - y/3b )

Step-by-step explanation:

Given----> x² / 4a² - y² / 9b²

To find-----> Factors of given expression

Solution-----> We know that,

a² - b² = ( a + b ) ( a - b )

4 = 2 × 2

= 2²

9 = 3 × 3

= 3²

Now,

x² / 4a² - y² / 9b²

= ( x / 2a )² - ( y / 3b )²

Now, applying above identity , we get,

= ( x / 2a + y / 3b ) ( x / 2a - y / 3b )

Additional information----->

1) ( a + b )² = a² + b² + 2ab

2) ( a - b )² = a² + b² - 2ab

3) ( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ca

4) ( a³ + b³ ) = ( a + b ) ( a² + b² - ab )

5) ( a³ - b³ ) = ( a - b ) ( a² + b² + ab )