Question

Factorise:
x^2 - 4ax - b^2 + 4a^2 = 0​

Answer 1

Answer:

Hey here's your answer.

Step-by-step explanation:

X^2-4ax+4a^2-b^2=0

x^2-2*2a*x+(2a)^2-(b)^2=0

(x-2a)^2-(b)^2=0

(x-2a-b)(x-2a+b)=0

x-2a-b=0 x-2a+b=0

x=b+2a x=2a-b

Therefore, x= 2a+b or 2a-b

Answer 2

Answer:

${x}^{2} - 4ax - {b}^{2} + 4 {a}^{2} \\ = ( {x}^{2} - 4ax + 4 {a}^{2} ) - {b}^{2} \\ = (( {x}^{2}) - 2(x)(2a) + ( {2a)}^{2} ) - {b}^{2} \\ = ( x - 2a - b)(x - 2a - b)$

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