Question

factorise (x^2+4x)^2+4x^2-2x^2y+16x-8xy​

Answer 1

Answer:

$(x^{2} +4x)[(x+2)^{2} -2y]$

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Step-by-step explanation: (x^2+4x)^2+4x^2-2x^2y+16x-8xy​

Answer 2

Answer:

(x2+4x2)+4x2-2x2y+16x-8xy  

Final result :

 -x • (2xy - 9x + 8y - 16)

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".  

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (((((x2)+(4•(x2)))+(4•(x2)))-(2x2•y))+16x)-8xy

Step  2  :

Equation at the end of step  2  :

 (((((x2)+(4•(x2)))+22x2)-2x2y)+16x)-8xy

Step  3  :

Equation at the end of step  3  :

 (((((x2)+22x2)+22x2)-2x2y)+16x)-8xy

Step  4  :

Step  5  :

Pulling out like terms :

5.1     Pull out like factors :

  -2x2y + 9x2 - 8xy + 16x  =  

 -x • (2xy - 9x + 8y - 16)  

Trying to factor a multi variable polynomial :

5.2       Split       2xy - 9x + 8y - 16  

            into two 2-term polynomials

             - 9x + 2xy   and     + 8y - 16

            This partition did not result in a factorization. We'll try another one:

            2xy - 9x   and     + 8y - 16

            This partition did not result in a factorization. We'll try another one:

            2xy + 8y   and     - 9x - 16

            This partition did not result in a factorization. We'll try another one:

            2xy - 16   and     + 8y - 9x

            This partition did not result in a factorization. We'll try another one:

             - 16 + 2xy   and     + 8y - 9x

            This partition did not result in a factorization. We'll try another one:

             + 8y + 2xy   and     - 9x - 16

           All three partitions failed. Tiger finds no factorization

Final result :

 -x • (2xy - 9x + 8y - 16)