Question

factorise. x^2+4x-21​

Answer 1

Answer:

The factors are (x + 7)(x - 3).

Step-by-step explanation:

Factorize the expression, x² + 4x - 21 = 0 as follows:

$x^{2}+4x-21=0\\x^{2}+7x-3x-21=0\\x(x+7)-3(x+7)=0\\(x+7)(x-3)=0$

Thus, the factors are (x + 7)(x - 3).

Answer 2

Step-by-step explanation:

(x+7)(x-3)

HOPE u had understood it

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