factorise (x^2-4x+4)-81
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It is may be correct............but I am sure
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johnfelixanthonycena:
sorry this a not a right answer
the thing u have done is only for rhs=0...bcox at that time we say if any one factor has its value =0 ,,the whole product will be zero,,,, but here we can't say if one factor is 81 then other will be 1 for same value of X,, in order to get product as 81
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(x-2)^2-(9)^2=(x-2-9)(x-2+9)
sorry it is not the right answer
then?
(x-11)(x+7) is not anser??? ....
(x-11)(x+7) is not anser??? ....
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