Question

Factorise : x^2 - 4x + 5

Answer 1

Answer:

Using identity -(a+b)(a+c)

= x²-5x+x-5

= x(x-5)+1(x-5)

= (x-5)(x+1)

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Answer 2

Correct Question :

Factorise : x² - 4x - 5

Solution :

We have to factorise : x² - 4x - 5

x² - 4x - 5 is in the form ax² + bx + c and is not equal to 0.

We have to find integers whose sum is "b" i.e. (-4) and product is (-5).

=> x² - 4x - 5

=> x² - 5x + x - 5

If we add -5 and +1 we get -4 i.e. "b" and if we multiple -5 and +1 we get -5 i.e. "c"

=> x² - 5x + x - 5

Take 'x' common from x² - 5x and '1' common from x - 5

=> x(x - 5) +1(x - 5)

x - 5 comes two times, write it one time

=> (x - 5) (x + 1)

(x - 5) (x + 1) are the factors of x² - 4x - 5.