Question

Factorise :
x^2-4x-5


you have to factorise it
and your would be (x-5)(x+1)​

Answer 1

Step-by-step explanation:

x^2-4x-5=0

x2-5x+x-5=0

x(x-5) -1(x-5) =0

(x-1) (x-5) =0

Answer 2

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\purple{R}}}}$

$x^{2} -4x -5=0$

$x^{2} -5x+1x-5=0$

$x(x-5)+1(x-5)$

$(x+1)(x-5)$