Question

factorise(x^2-4x)(x^2-4x-1)​

Answer 1

SOLUTION

(2−4)(2−4−1)

{(x^{2}-4x)(x^{2}-4x-1)}}(x2−4x)(x2−4x−1)

(2−4−1)⋅2−4(2−4−1)

4−43−12−4(2−4−1)

4−43−2−43+162+4

4−83−2+162+4

4−83−2+162+4

Answer 2

Step-by-step explanation:

Question:

(x²-4x)(x²-4x-1)

Solutions:

= [x²(x²-4x-1) -4x(x²-4x-1)]

= [(x⁴-4x³-x²)(-4x³+16x²+4x)]

= (x⁴-8x³-x²+16x²+4x)

= (x⁴-8x³+15x²+4x)