Question

factorise x^2+4y^2+4xy-4​

Answer 1

Answer:

2x+4y-8xy-1

2x-8xy and 4y-1

2x-8xy=0 and 4y-1

2x(1-4y)=0and 4y-1

1-4y=0/2x and 4y-1

(1-4y)(4y-1) is factors

Answer

Answer 2

Answer:

(x-2y+2)(x-2y-2)

Step-by-step explanation:

x²+4y²+4xy-4

((a+b)²=a²+2ab+b²)

(x-2y)²-4

(a²-b²=(a+b)(a-b))

(x-2y+2)(x-2y-2)

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