Question

Factorise: -x^2+55x-750

Answer 1

Given:-

→-x²+55x-750=p(x)

→p(x)=0

→-x²+55x-750=0

$\rule{200}{1}$

To Find:-

→The Value of x?

$\rule{200}{1}$

AnsWer:-

→-x²+55x-750=0

★Using Discriminant Formula, as Spiliting the middle term would be too lenghty★

→d=b²-4ac

•a=-1,b=55,c=-750

♦Putting the Values♦

→d=(55)²-4×-1×(-750)

→d=3025-3000

→d=3025

→√d=±√3025

→√d=±55

$\rule{200}{1}$

→Taking x(+)=$\frac{-b+ \sqrt{d}}{2a}$

→x=$\frac{-55+55}{2 \times 1}$

→x=$\frac{0}{2}$

→x=0

$\rule{200}{1}$

→Taking x(-)=$\frac{-b- \sqrt{d}}{2a}$

→x=$\frac{-55-55}{2×1}$

→x=$\frac{\cancel{-110}}{\cancel{2}}$

→x=-55

$\rule{200}{2}$

Answer 2

$\tt{\huge{\orange {Question - }}}$

Factorise: -x^2+55x-750

SOLUTION :

$\sf{ \leadsto{ - {x}^{2} + 55x - 750}}$

$\sf{ \leadsto{ - {x}^{2} - 30x - 25x + 750 \: }}$

$\sf{ \leadsto{ \: - x(x + 30) - 25(x + 30) \: }}$

$\sf{ \leadsto{( - x - 25)(x + 30)}}$

$\sf{ \leadsto{ - (x + 30)(x + 25) \: }}$