Factorise x^2-5x-24 by using the factor theorem.
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Question:
Factorise x²-5x-24 by using the factor theorem
Answer:
(x-8)(x+3)
Step-by-step explanation:
Here,
coefficient of the leading term is 1 and the constant term is -24.
A zero of the polynomial p(x) will be a factor of the number -24.By inspection, we find that the number 8 is a divisor of -24 and also we have ,
p(8)=(8)²-5(8)-24
⇒64-40-24=0
8 is a zero of the polynomial p(x).
Then (x-8) is a factor of the polynomial. We can express
x²-5x-24=(x²-8x)+(3x-24)
=x(x-8)+3(x-8)
=(x-8)(x+3)
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