factorise x^2+6√6x+48
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Answered by
14
Hello!
x² + 6√6 + 48 = 0
⇒ x² + 2√6x + 4√6x + 48 = 0
⇒ x ( x + 2√6 ) + 4√6 ( x + 2√6 ) = 0
⇒ ( x + 2√6 ) ( x + 4√6 ) = 0
⇒ x = -2√6 or x = -4√6
Cheers!
x² + 6√6 + 48 = 0
⇒ x² + 2√6x + 4√6x + 48 = 0
⇒ x ( x + 2√6 ) + 4√6 ( x + 2√6 ) = 0
⇒ ( x + 2√6 ) ( x + 4√6 ) = 0
⇒ x = -2√6 or x = -4√6
Cheers!
iHelper:
MARK AS BRAINLIEST :)
I don't think you need to find solution , as it is not given question that is = 0
Thanks! I'll edit :)
:-D
Answered by
13
Answer :
By Factorisation method,
x² + 6√6x + 48
x² + 2√6x + 4√6x + 48
x × ( x + 2√6 ) + 4√6 × ( x + 2√6 )
( x + 2√6 ) × ( x + 4√6 )
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