factorise x^2+6x-7....pls.......
Answers
Answered by
57
x^2 + 6x - 7 = 0
x^2 + 7x - x -7= 0
x(x+7)-1(x+7) = 0
(x+7)(x-1) = 0
Hence, after factorisation
x^2 + 6x - 7 = (x+7)(x-1)
x^2 + 7x - x -7= 0
x(x+7)-1(x+7) = 0
(x+7)(x-1) = 0
Hence, after factorisation
x^2 + 6x - 7 = (x+7)(x-1)
Answered by
29
here is your answer
as factorisation of the given equation is
(x+7)(x-1)
as factorisation of the given equation is
(x+7)(x-1)
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sourish8:
ei.....thanks
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