Question

factorise x^2+7root6x+60

Answer 1

x^2+7root6x + 60=0

so

x^2+ 5root6x+ 2root6x + 60= 0

then,

x (x+5root6) + 2root6 (x+5root6)=0

therefore,

(x+2root6)(x+5root6)=0

Answer 2

Answer:

+76x+60=

x ^{2} + 5 \sqrt{6} x + 2 \sqrt{6} x + 60x2+56x+26x+60

x(x + 5 \sqrt{6} ) + 2 \sqrt{6} (x + 5 \sqrt{6} )x(x+56)+26(x+56)

(x + 5 \sqrt{6} )(x + 2 \sqrt{6} )(x+56)(x+26)

so the zeroes are

- 2 \sqrt{6}−26

and

- 5 \sqrt{6}−56