Question

Factorise(x^2-7x)^2+18(x^2-7x)^2+72​

Answer 1

Answer:

Let x²-7x=a

Now our equation becomes a²+18a²+72

a²+12a+6a+72

(a²+12a)+(6a+72)

a(a+12)+6(a+12)

Final answer=(a+6)(a+12)

Answer 2

Answer:

$({x}^{2} - 7x) + 18( { {x}^{2} - 7x })^{2} + 72 = \\ {x}^{2} - 7x + 18( ({x {}^{2} )}^ {2} + {(7x)}^{2} - 14 {x}^{3} + 72 = \\ {x}^{2} - 7x + 18 {x}^{4} + 49 {x}^{2} - 14 {x}^{3} + 72 = \\ 18 {x}^{4} - 14 {x}^{3} + 49 {x}^{2} - 7x + 72 =$