factorise=x^2-9y^2+6y-1
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Answer:
x²-9y²+6y-1
x²-(9y²-6y+1)
x²-[(3y)²-2(3y)(1)+(1)²]
using a²-2ab+b²=(a-b)²
x²-(3y-1)²
using a²-b²=(a+b)(a-b)
[x-(3y-1)][x+(3y-1)]
(x-3y+1)(x+3y-1)
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