Question

factorise: x^2+(a-b)xy-aby^2

Answer 1

Answer:

xy= 0 , xy = -(a+b )

Step-by-step explanation:

x^2+(a-b)xy-abxy^2

comparing with ax^2+bx+c=0

a=1, b=(a-b) ,c=-ab

b^2-4ac = (a-b)^2 -(4×1×-ab)

= a^2-2ab+b^2+4ab

= a^2+2ab+b^2

=(a+b)^2

root(b^2-4ac)^2= +- (a+b)

xy =[ -b +- (root (b^2-4ac) ] /2a

=[ -(a-b) +-(a+b)] /2

xy= -( a-b)+(a+b) /2 or xy= -( a-b)- (a+b) /2

xy = -a -b +a +b/2 or xy = -a -b -a--b/2

xy =0 or xy = -( a+b)