Math, asked by karthimaranman, 8 months ago

factorise x^2+ root 3 x - 6

Answers

Answered by vrundamin
1

Answer:

Hey!!!....Here is ur answer

\begin{gathered}{x}^{2} - \sqrt{3} x - 6 \\ \\ = {x}^{2} - 2 \sqrt{3} x + \sqrt{3} x - 6 \\ \\ = x(x - 2 \sqrt{3} ) + \sqrt{3} (x - 2 \sqrt{3} ) \\ \\ = (x - 2 \sqrt{3} )(x + \sqrt{3} )\end{gathered}

x

2

3

x−6

=x

2

−2

3

x+

3

x−6

=x(x−2

3

)+

3

(x−2

3

)

=(x−2

3

)(x+

3

)

Hope it will help you

Answered by kcsahooxx
1

Answer:

=x2-2✔3x+✔3x-6

=x(x- 2✔3)+ ✔3(x-2✔3)

=(x+ ✔3)(x- 2✔3)answer

Step-by-step explanation:

Similar questions