factorise (x+2) square - (x+4) square
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Answer:
(x+2)^2- (x+4)^2
using identity a^2-b^2 = a+b)(a-b)
here a = X+ 2
b= X+ 4
[(X+2)+(X+4)] [(X+2)-(X+4)]
[X+X+2+4] [ X+2-X-4]
[ 2x+6] [ -2]
-2(2x+6)
-4x-12
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