Question

factorise x^2+ x+1/4

Answer 1

Given,

An equation x²+x+1/4.

To find,

The factors of the equation

Solution,

The equation is of the form of ax²+bx+c where a = 1, b = 1 and c = 1/4.

First, we need to find the discriminant of the equation.

⇒   D = b²-4ac

⇒   D = (1)² - 4(1)(1/4)

⇒   D = 1 - 1

⇒   D = 0.

Since D = 0 the equation must have equal roots.

$x=\frac{-b+\sqrt[]{D} }{2a}$

⇒  x = (-1 +√0)/2

⇒  x = -1/2.

Hence the factors of the equation  x²+x+1/4 are x = -1/2 and x = -1/2.

Answer 2

Step-by-step explanation:

An equation x²+x+1/4.

To find,

The factors of the equation

Solution,

The equation is of the form of ax²+bx+c where a = 1, b = 1 and c = 1/4.

First, we need to find the discriminant of the equation.

⇒ D = b²-4ac

⇒ D = (1)² - 4(1)(1/4)

⇒ D = 1 - 1

⇒ D = 0.

Since D = 0 the equation must have equal roots.

x=\frac{-b+\sqrt[]{D} }{2a}x=

2a

−b+

D

⇒ x = (-1 +√0)/2

⇒ x = -1/2.

Hence the factors of the equation x²+x+1/4 are x = -1/2 and x = -1/2.