factorise : x^2 + x/2 + x^2 - 4y^2
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You can write the expression as a difference of squares, then use a special factoring form:
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Here is the answer =>
Step-by-step explanation:
x^2+x/2+x^2-4y^2=0
2x^2+x/2=4y^2
4x^2+x=8y^2 (Multiplying both sides by 2).
(2x) ^2+(√x)^2=2√2y^2
So (2x+√x)^2-4x√x =2√2y^2
So (2x+√x) -4x√x=2√2y.
HOPE IT HELPS.
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