Question

Factorise: x^2 + x/4-1/8​

Answer 1

Answer:

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Answer 2

$\huge\bigstar\mathfrak\blue{\underline{\underline{SOLUTION:}}}$

${x}^{2} + \frac{x}{4} - \frac{1}{8} \\ \\ = > \frac{8 {x}^{2} + 2x - 1}{8} \\ \\ = > \frac{ {8x}^{2} + 4x - 2x - 1}{8} \\ \\ = > \frac{4x(2x + 1) - 1(2x + 1)}{8} \\ \\ = > \frac{(2x + 1)(4x - 1)}{8} \\ \\ = > \frac{(2x + 1)}{2} \frac{(4x - 1)}{4} \\ \\ = > (x + \frac{1}{2} ) \: (x - \frac{1}{4} )$

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