Question

factorise x^2-x-4 find it's zeros
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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

${x}^{2} - x - 4 = 0 \\ d = {b}^{2} - 4ac \\ d = {( - 1)}^{2} - 4(1)( - 4) \\ d = 1 + 16 \\ d = 17 \\ x = \frac{ - b + - \sqrt{d} }{2a}$