factorise x^2+x-6=0
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x²+x-6=0
Here, the factors of 6 that when subtracted give +1 are 3 and 2, so
x²+3x-2x-6=0
Taking (x+3) common,
x(x+3)-2(x+3)=0
(x-2)(x+3)=0
Answer=> (x-2)(x+3)
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