Question

factorise x^2+(x-7)^2= 169

Answer 1

$\underline{\large\bf{\mathfrak{Hello!}}}$

$= > {x}^{2} + {(x - 7)}^{2} = 169 \\ = > {x}^{2} + ( {x}^{2} + 49 - 14x) = 169 \\ = > {x}^{2} + {x}^{2} + 49 - 14x = 169 \\ = > 2 {x}^{2} - 14x + 49 - 169 = 0 \\ = > 2 {x}^{2} - 14x - 120 = 0 \\ = > 2( {x}^{2} - 7x - 60) = 0 \\ = > {x}^{2} - 7x - 60 = 0\\ = > {x}^{2} - 12x + 5x - 60 = 0 \\ = > x(x - 12) + 5(x - 12) = 0 \\ = > (x - 12)(x + 5) = 0 \\ \\ = > x = - 5 \\ \: \: \: \: \: \: \: \: x = 12$

$\boxed{x = -5 \: or \: 12}$

$\bf{\mathfrak{Hope \: this \: helps...:)}}$

Answer 2

Answer:

x=-5 & x=12

Step-by-step explanation:

=>x2+(x−7)2=169=>x2+(x2+49−14x)=169=>x2+x2+49−14x=169=>2x2−14x+49−169=0=>2x2−14x−120=0=>2(x2−7x−60)=0=>x2−7x−60=0=>x2−12x+5x−60=0=>x(x−12)+5(x−12)=0=>(x−12)(x+5)=0=>x=−5x=12