Question

factorise x^2-x-72
pls answer this question someone
pls don't give unnecessary answers
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Answer 1

Answer:

x² - x - 72

Grouping

1

Use the sum-product pattern

x²-x-72

x² +8x-9x - 72

2

Common factor from the two pairs

x² + 8x - 9x - 72

x(x + 8) 9(x + 8)

3

Rewrite in factored form

x(x + 8) - 9(x+8)

(x −9)(x + 8)

answer:

(x −9)(x + 8)

Answer 2

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$Given: x2−x−72$

$=x2−9x+8x−72,$

$=(x2−9x)+(8x−72),   \\  (group \: pair \: of \: terms )$

$=x(x−9)+8(x−9),$

$(factor \: each \: binomials)$

$=(x−9)(x+8),$

$(factor \: out \: common \: factor (x−8))$

$Hence \: the \: factors \: \\ of x2−x−72 are (x−9)(x+8)$