factorise : x^2 - y^2 -6 ax + 2 ay + 8 a^2
a+b+c=0 , find value of a^2\bc + b^2\ca +c^2\ab
please do this fast
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Answer:
ax
2
−bx
2
+ay
2
−by
2
+az
2
−bz
2
Re-arranging the above we get,
ax
2
+ay
2
+az
2
−bx
2
−by
2
−bz
2
Take out common in all terms,
a(x
2
+y
2
+z
2
)−b(x
2
+y
2
+z
2
)
(x
2
+y
2
+z
2
)(a−b)
Step-by-step explanation:
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