factorise: x^2-y^2/9
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Given : x2−y2+6y−9
We can further write it as
x2−y2+6y−9=x2−(y2−6y+9)
So we get
x2−y2+6y−9
=x2−(y2−2×y×3+32)
=x2−(y−3)2
Now, based on the equation a2−b2=(a+b)(a−b)
We get,
x2−y2+6y−9=[x+(y−3)][x−(y−3)]
=(x+y−3)(x−y+3)
Hence we have factorised the above expression.
Answered by
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Answer:
Step-by-step explanation:
x² - y²/9 = (x)²- (y/3)²
= [x - y/3] [x + y/3]
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