Math, asked by rajveerghule2012, 5 hours ago

factorise: x^2-y^2/9​

Answers

Answered by SuryaDevil1290
2

Answer:

Answer

Open in answr app

Given : x2−y2+6y−9

We can further write it as

x2−y2+6y−9=x2−(y2−6y+9)

So we get

x2−y2+6y−9

=x2−(y2−2×y×3+32)

=x2−(y−3)2

Now, based on the equation a2−b2=(a+b)(a−b)

We get,

x2−y2+6y−9=[x+(y−3)][x−(y−3)]

=(x+y−3)(x−y+3)

Hence we have factorised the above expression.

Answered by eklavyadilipjha
0

Answer:

Step-by-step explanation:

x² - y²/9 = (x)²- (y/3)²

             = [x - y/3] [x + y/3]

Similar questions