Question

factorise (x^2+y^2-z^2)^2 - 4x^2y^2​

Answer 1

Answer:

it is right answer like it

Answer 2

Answer:

x^2+y^2-z^2)^2 - 4x^2y^2

( [ (x^2 + y^2 - z^2 ] + 2xy ) ( [ x^2 + y^2 -z^2] - 2xy )

( [ x^2 + 2xy + y^2 ] - z^2 ) ( [ x^2 - 2xy + y^2] - z^2 )

( ( x + y)^2 - z^2 ) ( ( x - y)^2 - z^2 )

( (x + y) + z ) ( (x + y ) - z ) ( (x - y) + z) ( ( x - y) - z )

( x + y + z ) ( x + y - z) ( x - y + z ) ( x - y - z )