Question

Factorise
x^2(y^2-z^2)+y^2(z^2-x^2)+z^2 (x^2-y^2)

Answer 1

Answer:

0

Step-by-step explanation:

=x²(y²-z²) + y²(z²-x²) + z²(x²-y²)

=x²y²-x²z² + y²z²-y²x² + z²x²-z²y²

=(x²y²-y²x²) + (y²z²-z²y²) + (z²x²-x²z²)

= 0+0+0

=0