Factorise x + 2x^2 - 528 by discriminant method
Answers
Answered by
8
★★Heya★★
Given QUADRATIC POLYNOMIAL is
2x² + x - 528 = 0
It's Roots are
x = { -b ±√(D) } / 2a
Here, b = 1 , a = 2 And
D = ( 1 )² - 4 ( 2 ) ( -528 )
D = 4225
=>
x ±{ -1 ± √(4225) } /4
=>
x ± { -1 ± 65 } / 4
=>
{x -33/2} × { x + 16 }
Given QUADRATIC POLYNOMIAL is
2x² + x - 528 = 0
It's Roots are
x = { -b ±√(D) } / 2a
Here, b = 1 , a = 2 And
D = ( 1 )² - 4 ( 2 ) ( -528 )
D = 4225
=>
x ±{ -1 ± √(4225) } /4
=>
x ± { -1 ± 65 } / 4
=>
{x -33/2} × { x + 16 }
Answered by
6
AnswEr :
Given :
Factorise: x + 2x² - 528
To Find :
By discriminant method :
Explanation :
As ax² + bx + c = 0 compared with given equation (2x² + x - 528 = 0) :
- a = 2
- b = 1
- c = -528
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