Factorise :(x-2y)^2-12(x-2y)+32. Plz answer fast its very urgent
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Answered by
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Let (x-2y) = a
a²-12a+32
=a²-4a-8a+32
=a(a-4) -8(a-4)
=(a-4) (a-8)
substitute the value of a
so the factors are
(x-2y-4) (x-2y-8)
a²-12a+32
=a²-4a-8a+32
=a(a-4) -8(a-4)
=(a-4) (a-8)
substitute the value of a
so the factors are
(x-2y-4) (x-2y-8)
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