Question

factorise: (x-2y)^2+4x-8y

Answer 1

${(x - 2y)}^{2} + 4x - 8y \\ = (x - 2y)(x - 2y) + 4(x - 2y) \\ = (x - 2y)(x - 2y + 4)$
it's may be right I'm not sure

Answer 2

Polynomial expression can be factorise as shown below:

$\bf \red{{(x - 2y)}^{2} + 4x - 8y = (x - 2y)(x - 2y + 4) }$.

Given:

• ${(x - 2y)}^{2} + 4x - 8y$

To find:

• Factors of given polynomial expression.

Solution:

Step 1:

Rewrite the expression.

Take 4 common from last two terms.

${(x - 2y)}^{2} + 4(x - 2y )$

Step 2:

Take (x-2y) common from both terms.

${(x - 2y)}(x - 2y) + 4(x - 2y )$

or

$= (x - 2y)(x - 2y + 4)$

Thus,

Factors are $\bf {(x - 2y)}^{2} + 4x - 8y = (x - 2y)(x - 2y + 4)$

Learn more:

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