Question

factorise (x−2y)^2 +4x −8y
please answer
​
​

Answer 1

Answer:

x - 2y(x - 2y + 4)

Step-by-step explanation:

Given : (x - 2y)² + 4x - 8y

On solving further, we get

→ (x - 2y)² + 4(x - 2y)

→ (x - 2y)(x - 2y) + 4(x - 2y)

→ x - 2y(x - 2y + 4)

Answer 2

Answer:

$(x-2y+4)(x-2y)$

Step-by-step explanation:

$(x-2y)^{2} +4x-8y$

⇒$(x-2y)(x-2y)+4(x-2y)$

∴$(x-2y+4)(x-2y)$

Hence the factorisation of $(x-2y)^{2} +4x-8y$ is $(x-2y+4)(x-2y)$