factorise (x-2y)^2 - 6(x-2y)+5
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(x−2y)
2
−6(x−2y)+5
Let x−2y=z
Then,(x−2y)
2
−6(x−2y)+5 becomes
=z
2
−6z+5
=z
2
−5z−z+5
=z(z−5)−1(z−5)
=(z−5)(z−1)
Now, on subtituting z=x−2y,we get
=[(x−2y)−5][(x−2y)−1]
=(x−2y−5)(x−2y−1)
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