Math, asked by nanditha25, 7 months ago

Factorise : (x+2y)^3 + (2x+y)^3

Answers

Answered by anandgeetha2302

Answer:

Evaluate : (2x-y)3 = 8x3-12x2y+6xy2-y3

1.2 Evaluate : (x-2y)3 = x3-6x2y+12xy2-8y3

Step 2 :

Pulling out like terms :

2.1 Pull out like factors :

9x3 - 18x2y + 18xy2 - 9y3 =

9 • (x3 - 2x2y + 2xy2 - y3)

Checking for a perfect cube :

2.2 x3 - 2x2y + 2xy2 - y3 is not a perfect cube

Final result :

9 • (x3 - 2x2y + 2xy2 - y3)

Step-by-step explanation:

Answered by BRAINLYADDICTOR

102

$<marquee behaviour-move><h1>ANSWER:</ ht></marquee>$

➡️(x+2y)^3 + (2x+y)^3

➡️X^3+(2y)^3+3x^2(2y)+3x(2y)^2+

(2x)^3+y^3+3(2x)^2(y)+3(2x)y^2

➡️X^3+8y^3+6x^2y+12xy^2

+8x^3+y^3+12x^2y+6xy^2

➡️X^3+8x^3+8y^3+y^3+6x^2y

+12x^2y+12xy^2+6xy^2

➡️9x^3+9y^3+18x^2y+18xy^2

➡️9(x^3+y^3+2x^2y+2xy^2)

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