Question

Factorise (x-2y) the whole cube + (2y-3z) the whole cube + (3z-x) the whole cube


Help me do it with the steps.
Plsss

Answer 1

Answer:

given (x-2y)^3 + (2y-3z)^3 + (3z-x)^3

we know that if a + b + c = 0

then a^3 + b^3 + c^3 = 3abc

here a = (x-2y)

b = (2y-3z)

c = (3z-x)

(x-2y)^3 + (2y-3z)^3 + (3z-x)^3 = 3(x-2y)(2y-3z)(3z-x)