Math, asked by RobertDowry, 9 months ago

factorise x^3-1
please it's important I will mark brainliest​

Answers

Answered by mysticd
0

Answer:

x³-1 = (x-1)(x²+x+1)

Step-by-step explanation:

-1

= -1³

= (x-1)(+x*1+1²)

/* By algebraic identity:

-b³ = (a-b)(+ab+) */

= (x-1)(+x+1)

Therefore,

x³-1 = (x-1)(x²+x+1)

Answered by winner857
0

a=x,b=1

x^3-1^3

=a^3 - b^3

(a+b)(a^2 - b^2 - ab)

=(x+1)(x^2 - 1 - x)


mysticd: it is wrong
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