Question

Factorise x^3+1/x^3-2​

Answer 1

Answer:

Step-by-step explanation:

x^3 + 1/x^3 - 2

=x^3+1/x^3+1 -3

=(x)^3+(1/x)^3 +(1)^3–3.x.1/x.1

=(x+1/x+1)(x^2+1/x^2+1^2-x.1/x-1/x.1–1.x)

=(x+1/x+1)(x^2+1/x^2+1–1–1/x-x)

=(x+1/x+1)(x^2+1/x^2–1/x-x)

Answer 2

Answer:

a^3+.b^3+c^.3-3.a.b.c=(a+b+c) (a^2+b^2+c^2-a.b-b

c-ca)............................................................................................(1)

x^3+1/x^3-2

=x^3+1/x^3+1-3

=(x)^3+(1/x)^3+(1)^.3-3.x.1/x.1

=(x+1/x+1)(x^2+1/x^2+1^2-x.1/x-1/x.1-1.x

=(x+1/x+1)x^2+1/x^2+1-1-1/x-x)

=(x+1/x+1)(x^2+1/x^2-1/x-x),................(answer)

Answer 3

Answer:

a^3+.b^3+c^.3-3.a.b.c=(a+b+c) (a^2+b^2+c^2-a.b-b

c-ca)............................................................................................(1)

x^3+1/x^3-2

=x^3+1/x^3+1-3

=(x)^3+(1/x)^3+(1)^.3-3.x.1/x.1

=(x+1/x+1)(x^2+1/x^2+1^2-x.1/x-1/x.1-1.x

=(x+1/x+1)x^2+1/x^2+1-1-1/x-x)

=(x+1/x+1)(x^2+1/x^2-1/x-x),................(answer)