Question

factorise x^3-1+y^3+3xy​

Answer 1

Answer:

here is ur answer dear

Step-by-step explanation:

x^3 - 1+ y^3 + 3xy = (x)^2 + ( -1)^ 3 + y^3 -3 × x× (-1) × (-1) ×y

w.k.t; a^3 + b^3 +c^3 - 3abc = ( a+b+c)

(a^2+ b^2 + c^2 - ab + bc - ca )

x3- 1+ y^3 + 3xy = { x+ (- 1) +y }

{ ( x ) ^ 2 + ( -1 )^2 + ( y ) ^ 2 - (x) (-1) - (-1 ) (y) - (x) }

= ( x-1+ y) ( x^2 +1 +y2 + x + y - xy )

hello this is ur answer