Factorise x^3+13x^2+32x+20
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Answered by
22
p(x) = x³ + 13x²+ 32x + 20
Put x = –1 in p(x),
p(–1) = (–1)³+ 13(–1)² + 32(–1) + 20
= (–1) + 13 + (–32) + 20
= 33 – 33 = 0
So, (x + 1) is a factor of p(x)
divide p(x) with (x + 1), we get x²+ 12x + 20
∴ p(x) = (x + 1)(x² + 12x + 20)
⇒ p(x) = (x + 1)(x² + 10x + 2x + 20)
= (x + 1)[x(x + 10) + 2(x + 10)]
= (x + 1)(x + 10)(x + 2) Hope it helps
Put x = –1 in p(x),
p(–1) = (–1)³+ 13(–1)² + 32(–1) + 20
= (–1) + 13 + (–32) + 20
= 33 – 33 = 0
So, (x + 1) is a factor of p(x)
divide p(x) with (x + 1), we get x²+ 12x + 20
∴ p(x) = (x + 1)(x² + 12x + 20)
⇒ p(x) = (x + 1)(x² + 10x + 2x + 20)
= (x + 1)[x(x + 10) + 2(x + 10)]
= (x + 1)(x + 10)(x + 2) Hope it helps
Answered by
6
p(x) = x³ + 13x²+ 32x + 20
Put x = –1 in p(x),
p(–1) = (–1)³+ 13(–1)² + 32(–1) + 20
= (–1) + 13 + (–32) + 20
= 33 – 33 = 0
So, (x + 1) is a factor of p(x)
divide p(x) with (x + 1), we get x²+ 12x + 20
∴ p(x) = (x + 1)(x² + 12x + 20)
⇒ p(x) = (x + 1)(x² + 10x + 2x + 20)
= (x + 1)[x(x + 10) + 2(x + 10)]
= (x + 1)(x + 10)(x + 2) Hope it helps
Put x = –1 in p(x),
p(–1) = (–1)³+ 13(–1)² + 32(–1) + 20
= (–1) + 13 + (–32) + 20
= 33 – 33 = 0
So, (x + 1) is a factor of p(x)
divide p(x) with (x + 1), we get x²+ 12x + 20
∴ p(x) = (x + 1)(x² + 12x + 20)
⇒ p(x) = (x + 1)(x² + 10x + 2x + 20)
= (x + 1)[x(x + 10) + 2(x + 10)]
= (x + 1)(x + 10)(x + 2) Hope it helps
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