Question

Factorise x^3+13x^2+32x+20​

Answer 1

THIS IS YOUR ANSWER BRO!!!!

Answer 2

Answer:

Let p(x) = $x^{3}$ + $13x^{2}$+ 32x + 20

p(-1) = -1 + 13 - 32 + 20 = -33 + 33 = 0

Therefore (x + 1) is a factor of p(x).

On dividing p(x) by (x + 1) we get

p(x)  (x + 1) = $x^{2}$ + 12x + 20

Thus,

$x^{3}$ + $13x^{2}$ + 32x + 20 = (x + 1)($x^{2}$ + 12x + 20)

= (x + 1) ($x^{2}$ + 10x + 2x + 20)

= (x + 1)[x(x + 10) + 2(x + 10)]

= (x + 1) (x +2) (x + 10)

Hence, $x^{3}$ + $13x^{2}$ + 32x + 20 = (x + 1) (x +2) (x + 10).

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